Honors lab Chemistry Essay

0.032 gVolume of turgidity a plenty (mL)30mLBarometric pressure ( atmosphere)1.1 atmRoom Temperature (C)22 Cvapour pressure of the water (torr)19.8 torrCalculations1. redeem the balanced equation for the reaction conducted in this lab, including appropriate phase symbols. (2 points)Mg(s) + 2HCl(a) + H2O(a) -> MgCl2(s) + H2 (g)2. Determine the partial derivative pressure of the total heat natural turgidness collected in the swash collection tube-shaped structure. (3 points)1.1 atm = 0.026 atm + h23. Calculate the molees of hydrogen gunslinger collected. (4 points) n = 1.074 atm x 0.03 L / 0.0821 x 295.15 K = 0.00133 mol H24. If atomic number 12 was the limiting reactant in this lab, calculate the theoretic yield of the gaseous product. Show altogether steps of your calculation. (4 points).032 g Mg * 1 mol Mg / 24.305 g Mg * 1mol h2 / 1 mol Mg = 0.0131 mol5. Determine the percent yield of this reaction, presentation all steps of your calculation. (3 points)Percent appl y = 0.00133 /0.0131 mol H2 100 = 10. 15 % mop up1. Would the following errors increase, decrease, or have no effect on the calculated moles of gas collected in the experiment? explicate your answers in complete sentences.a) The measured mass of the magnesium was smaller than the true mass. (3 points)It would non happen upon the number of moles calculated because it was not used to measure the moles of the gas.b) The actual temperature of the hydrogen gas is less than room temperature. (3 points)If the gas was cooler than its surroundings, its density would be greater, and the gaudiness would appear to be smaller. Charles Law says that a gas volume is directly relative to its temperature, if the pressure on it is constant.2. rationalize in terms of particle collisions and Daltons law of nature why it can be fictitious that the total pressure inside the gas collection tube is equal to the atmospherical pressure outdoor(a) of the tube. (4 points)The particles inside the conta iner atomic number 18 exerting force on the walls of the container, while the particles outside of the container are also exerting force. If there were every less pressure from the inside, the tube would collapse. If there were any less pressure from the outside, the tube would explode.3. If an undetected air bubble was confine inside the gas collection tube, how would this affect your calculated percent yield? Explain your answer. (4 points) The bubble would take up outer space in the container and the volume would decrease. Therefore the persona yield would be incorrect.